(2x-12)(x^2+1)=0

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Solution for (2x-12)(x^2+1)=0 equation: 


Simplifying
(2x + -12)(x2 + 1) = 0

Reorder the terms:
(-12 + 2x)(x2 + 1) = 0

Reorder the terms:
(-12 + 2x)(1 + x2) = 0

Multiply (-12 + 2x) * (1 + x2)
(-12(1 + x2) + 2x * (1 + x2)) = 0
((1 * -12 + x2 * -12) + 2x * (1 + x2)) = 0
((-12 + -12x2) + 2x * (1 + x2)) = 0
(-12 + -12x2 + (1 * 2x + x2 * 2x)) = 0
(-12 + -12x2 + (2x + 2x3)) = 0

Reorder the terms:
(-12 + 2x + -12x2 + 2x3) = 0
(-12 + 2x + -12x2 + 2x3) = 0

Solving
-12 + 2x + -12x2 + 2x3 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-6 + x + -6x2 + x3) = 0

Ignore the factor 2.

Subproblem 1
Set the factor '(-6 + x + -6x2 + x3)' equal to zero and attempt to solve:

Simplifying
-6 + x + -6x2 + x3 = 0

Solving
-6 + x + -6x2 + x3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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